10m^2=4

Solution for 10m^2=4 equation:

10m^2=4

We move all terms to the left:

10m^2-(4)=0

a = 10; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·10·(-4)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{10}}{2*10}=\frac{0-4\sqrt{10}}{20}
=-\frac{4\sqrt{10}}{20}
=-\frac{\sqrt{10}}{5}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{10}}{2*10}=\frac{0+4\sqrt{10}}{20}
=\frac{4\sqrt{10}}{20}
=\frac{\sqrt{10}}{5}
$